How long will it take for the moon to get back to its original position? (its orbital period)!!?
Assume the moon moves in acircle around the Earth. if the Earth moon distance is 3.8×10^8m, how fast is the moon moving? Plaese show all work including substitutions
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Tagged with: 8m • earth moon • moon distance • Moon Moves • Moving • Orbital Period
Filed under: How To Get Him Back
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Are you asking for both velocity and period? It looks like you are.
"E" means 10 raised to the power of "x" just in case you don’t know. It’s easier to use on a computer.
Values needed:
Radius of Earth (R) = 3.8E+8 m
Mass of Earth (M) = 5.9736E+24 kg
Universal Gravitational Constant (G) = 6.673E-11 N*m^2/kg^2.
Velocity (V) = SQRT [ GM / R ]
V = SQRT { [ (6.673E-11) * (5.9736E+24) ] / (3.8E+8) }
V = SQRT { 398,618,328,000,000 / 3.8E+8 }
V = SQRT { 1,048,995.6 }
V = 1,024.2 m/s
VELOCITY = 1,024.2 m/s
PERIOD (T) = (2 * pi * R) / V
T = (2 * pi * 3.8E+8) / 1,024.2
T = 2,387,610,416 / 1,024.2
T = 2,331,195 s
PERIOD = 2,331,195 seconds
Which equals: 26 days, 23 hours, 33 minutes, 15 seconds.
The real lunar period is 27.3 days, if you look it up, so this must be the right answer.
However, what would have actually pushed it over the top and into the exact right answer would have been using 384,403,000 meters as the distance, not 380,000,000 meters, which is slightly shorter.
not gonna do your homework but take that distance into 28 days (full moon cycle), if you assume they want hours, just do some division (for how much distance in 1 day), then do some multiplication (24 hrs to a day.)